CHEMICAL BONDING
Week: FOUR Date: Time:
Period: Duration: Average age of learners:
Subject: CHEMISTRY Class: SS ONE
Topic: CHEMICAL COMBINATION
Sub – Topic: Dative bond, Metallic bond and secondary bond
Reference materials:
(1) ESSENTIAL CHEMISTRY, TONALD PUBLISHERS, I. O ODESINA[ 4th Edition] pg58-68
(2) NEW SCHOOL CHEMISTRY, AFRICAN FIRST PUBLISHERS, OSEI YAW ABABIO
(3) INTERNET
Instructional materials: PERIODIC TABLE
Entry behavior: The students have been taught how to write electronic configuration
Behavioural objective: At the end of the lesson the students should be able to:
1st PERIOD
Explain dative bond with relevant examples
Explain metallic bond with relevant examples
2nd PERIOD
Explain Hydrogen bond with relevant example
Explain Van der waal forces with relevant examples
3rd PERIOD
Revision on chemical combination
CHEMICAL BONDING (continue)
1st PERIOD
STEP I: The teacher explains co-ordinate bond with relevant example
Co-ordinate Bond / Dative bond
Certain
atoms which have complete octets can donate their valence electrons which are
not involved in bond formation ,to other atoms, which are short of electron.
These donated electrons are, therefore, lone pair of electrons and are shared
by both the atoms.
When
in the formation of a bond, the electron pair is donated by one atom but shared
by both the atoms so as to complete their octets, the bond formed is
called co-ordinate bond or dative
bond.
Bond
is represented by an arrow pointing from the donor to the acceptor.
Bond
has some polar character, it is also known as dative or semi-polar bond or
co-ionic bond.
FACTORS
WHICH FAVOUR THE FORMATION OF DATIVE BOND
Vacant/empty
orbital in one atom
Presence
of lone pair of electrons (in another)
Example of dative bond
1)Ammonia with Boron trifluoride
In
ammonia, nitrogen has 5 valence electrons. Out of these ,3 electrons are shared
by 3 hydrogen atoms to form ammonia molecule while the remaining two electrons
form a lone pair, which can be donated to any electron deficient atom or
molecule.
In
BF3 molecule, boron is short of 2 electron.So to complete its
octet, it shares the lone pair of nitrogen ,forming a dative bond.

2)Sulphur
dioxide
Sulphur
as well as oxygen atoms have 6 valence electrons and each is a short of 2
electrons to complete its octet. Sulphur atom and oxygen atom ,share two
electrons each thus forming a double bond between them .Sulphur atom still has
4 unshared electrons i.e. two lone pairs to donate.Sulphur donates 1 lone pair
to oxygen atom, forming a co-ordinate bond between sulphur and a molecule of
Sulphur dioxide.By accepting this lone pair, octet of oxygen is also completed.

STEP II: The teacher explains Metallic bond with relevant example
METALLIC BOND
Metallic bonds are
strong, so metals can maintain a regular structure and usually have high
melting and boiling points.

Atomic
structure of a metal
Metals
are good conductors of electricity and heat, because the free
electrons carry a charge or heat energy through the metal. The free electrons
allow metal atoms to slide over each other, so metals are malleable and ductile.
EVALUATION
The teacher assesses the lesson by asking the following questions:
Briefly explain co-ordinate bond
Explain metallic bond
2nd
PERIOD
STEP I : The teacher explains Hydrogen bond with relevant example
HYDROGEN
BOND
A hydrogen bond is a special type of dipole-dipole attraction which occurs when a hydrogen atom bonded to a strongly electronegative atom exists in the vicinity of another electronegative atom with a lone pair of electrons. These bonds are generally stronger than ordinary dipole-dipole and dispersion forces, but weaker than true covalent and ionic bonds. Without hydrogen, bonding earth would have no water cycle, no ocean, no floating ice, no life as we know it.
In order for a hydrogen bond to occur, there must be both a hydrogen donor and an acceptor present. The donor in a hydrogen bond is the atom to which the hydrogen atom participating in the hydrogen bond is covalently bonded, and is usually a strongly electronegative atom such as N, O, or F. The hydrogen acceptor is the neighboring electronegative ion or molecule and must possess a lone-pair electron in order to form a hydrogen bond.
Since the hydrogen donor is strongly electronegative, it pulls the covalently bonded electron pair closer to its nucleus, and away from the hydrogen atom. The hydrogen atom is then left with a partial positive charge, creating a dipole-dipole attraction between the hydrogen atom bonded to the donor, and the lone electron pair on the acceptor.
STEP II: The teacher explains Van der waal’s forces with relevant example
Van der Waals' forces
Van
der Waals' forces are forces of attraction which exist between all atoms and
molecules. Van der Waals' forces are much weaker than all other types of
bonding.
They
are only significant in atoms and molecules which have no other types of
intermolecular forces of attraction, for example, discrete non-polar molecules
and the Group 0 elements.
Van
der Waals' forces are a result of electrostatic attraction between temporary
dipoles and induced dipoles caused by movement of electrons in atoms and
molecules.

The strength of Van der Waals' forces is related to the size of atoms and molecules. The bigger the atom or molecule the bigger the Van der Waals' force.
EVALUATION
The teacher assesses the lesson by asking the following questions:
Briefly explain Hydrogen bond
Explain van dan waal’s forces
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