ELECTROLYSIS
Week: THREE Date: 27-31/05/2019 Time:
Period: Duration: 1 HR
20 MIN. Average
age of learners: 16YEARS
Subject: CHEMISTRY Class:
SS TWO
Topic: ELECTROLYSIS
Sub topic: Reference materials:
(1) ESSENTIAL CHEMISTRY, TONALD PUBLISHERS, I. O ODESINA
(2) NEW SCHOOL CHEMISTRY, AFRICAN FIRST PUBLISHERS, OSEI YAW ABABIO
(3) INTERNET
Instructional
materials:
Entry behavior:
The students have been taught chemical reaction
Behavioural objective: At the end of the lesson the students should be able to:
i. Define electrolysis
ii. Differentiate between metallic conductor and electrolytic conductor
iii. State the factors that affect preferential discharge of ion
iv. Explain electrolysis of some electrolytes
CONTENT
ELECTROLYSIS
Electrolysis is
the process of decomposing (breaking down) an ionic substance,
called an electrolyte, into simpler substances using electricity.
The chemical reaction of electrolysis occurs when an electric current is passed
through a solution containing ions (ions are charged atoms,
they have more or less electrons than protons which causes an imbalance, the
overall charge can be negative or positive).
Conductors and Non Conductors
Substances around us
can be divided into two classes based on their ability of conduct electricity:
Non-Conductors: Those substances which do not allow electric current to
pass through them are called non-conductors or insulators. Example: - wood,
plastic glass, rubber etc.
Conductors: Those substances which allow electric current to flow
through tem are called conductors. Examples: Copper, Iron, Gold, Silver,
Graphite, salt solution etc.
Conductors can further
be divided into two groups
I.Metallic Conductors: These conductors conduct electricity or
electric current by movement of electrons without undergoing any chemical
change during the process. These conduct electricity in both solid as well as
molten state. Example: All the metals and Graphite
II.Electrolytes: Those substances which conduct electricity only when they are
present in aqueous solution and not in solid form are called electrolytes.
These conduct electricity by movement of ions in solutions.
Comparison of
Electrolytic and Metallic Conduction
S.No |
Metallic Conduction |
Electrolytic Conduction |
1 |
Electric
current flows by movement of electrons. |
Electric
current flows by movement of ions. |
2 |
No
chemical change occurs. |
Ions
are oxidized or reduced at the electrodes. |
3 |
It
does not involve the transfer of any matter. |
It
involves transfer of matter in the form of ions. |
4 |
Ohm's
law is followed. |
Ohm's
low is followed. |
5 |
Resistance
increases with increase of temperature. |
Resistance
decreases with increase of temperature. |
6 |
Faraday
law is not followed. |
Faraday
law is followed. |
TERMS
IN ELECTROLYSIS
Electrolysis |
decomposition of compound using
electricity |
Electrolyte |
an ionic compound which conducts
electric current in molten or aqueous solution, being decomposed in the
process. |
Electrode |
a rod or plate where electricity
enters or leaves electrolyte during electrolysis. |
Discharge |
the removal of electrons from
negative ions to form atoms or the gain of electrons of positive ions to
become atoms. |
Anode |
positive electrode connected to
positive terminal of d.c. source. Oxidation occurs here. Anode loses negative charge as
electrons flow towards the battery, leaving anode positively charged. This causes anion to discharge
its electrons here to replace lost electrons and also, negative charge are
attracted to positive charge. |
Cathode |
negative electrode connected
to negative terminal of d.c. source. Reduction occurs here. Cathode gains negative charge as
electrons flow from the battery towards the cathode, making cathode
negatively charged. This causes cation to be attracted
and gains electrons to be an atom. |
Anion |
negative ion attracted to
anode. |
Cation |
positive ion attracted to
cathode. |
TYPES
OF ELECTROLYTES
Non-electrolytes |
Weak electrolytes |
Strong
electrolytes |
Organic liquids
or solutions |
Weak acids and alkalis |
Strong acids, alkalis
and salt solutions |
ethanol C2H5OH |
limewater Ca(OH)2 |
aqueous sulphuric acid
H2SO4 |
For the electrolyte to conduct electricity, it must be:
An ionic compound (I) In molten (II) In aqueous state
The process of Electrolysis: Electrolysis of an
ionic substance
i.
The ionic substance is heated until it
melts.
ii.
The ions are able to move freely after the ionic substance is melted.
iii.
The power supply is connected and the electrodes are charged.
iv.
The ions move to the oppositely charged electrode (the negative electrons move
to the positive electrode, called the anode, and the positive electrons move to
the negative electrode, called the cathode).
v.
The electrodes give/take electrons from
the ions which makes the ions neutral.
vi. The ions become atoms (because they are neutral) and are deposited onto the electrode. At the cathode, the ion gain electrons to become atom, this is reduction while at the anode the ions loose electrons to become atom, this is oxidation.
Electrolysis of Molten Compounds
Molten/aqueous ionic compounds conduct electricity because
ions free to move.
In solid state, these ions are held in fixed
position within the crystal lattice.
Hence solid ionic compounds do not conduct
electricity.
When molten binary compound is electrolysed, metal
is formed on cathode while non-metal is formed on anode.
Electrolysis of
molten PbBr2
To make molten lead(II) bromide, PbBr2,
we strongly heat the solid until it melts. To electrolyse it, pass current
through the molten PbBr2.
What happens:
Ions present: Pb2+ and Br-
Reaction at Anode
Br- loses electrons at anode to become Br
atoms. Br atoms created form bond together to make Br2 gas.
2Br-(aq) --> Br2(g)+
2e-
Reaction at Cathode
Pb2+ gains electrons at cathode to become Pb atoms
becoming liquid lead (II).
Pb2+(aq) + 2e- --> Pb(l)
Overall equation
PbBr2(l) --> Pb(l) + Br2(g)
Electrolysis of Aqueous
Solution
Aqueous solutions contain additional H+ and
OH- ions of water, totaling 4 ions in the solution :
2 from electrolyte, 2 from water. Only 2 of
these are discharged.
FACTORS THAT AFFECTS THE PREFERENTIAL DISCHARGE OF ION
Thus, Selection of ions for preferential discharge is based on the following three factors:
I.
POSITION
OF IONS IN THE ELECTROCHEMICAL SERIES
For the electrolyte to conduct electricity, it must be Electrolysis
of aqueous solutions use the theory of selective discharge.
Increasing ease of
discharge [NOTE: KING
NOSIRU CAN MAKE A ZOO IN SAJE OR PANSEKE HAVING COLLECTED SOLID GOLD.]
If two or more positive ion migrate to the cathode,
it is the ion lowest in the electrochemical series (e.c.s) that is discharged
preferentially.
Example: Cu2+ are discharge in preference to H+
while H+ are discharge in preference to Na+. It will be recalled that the
reactivity series gives the order of the tendency of metals to form ions.
Metals at the top of the series have the greatest tendency to form ions and are
therefore the most difficult to discharge at the cathode.
If two or more negative ions migrate to the anode,
the ion lower in e.c.s is discharged preferentially.
II.
CONCENTRATION
OF THE IONS IN THE ELECTROLYTE
At cathode
In CONCENTRATED solutions of nickel/lead compound, nickel/lead
will be discharged instead of hydrogen ions of water which is less reactive
than nickel/lead.
In VERY DILUTE solutions, hydrogen,
copper and silver ions are preferable to be discharged, according to its ease
to be discharged.
Reactive ions (potassium, sodium, calcium,
magnesium, aluminium) will NEVER BE DISCHARGED in either
concentrated or dilute condition. Instead, hydrogen ions from water will be
discharged at cathode.
At anode
In CONCENTRATED solutions, iodine/chlorine/bromine ions are
preferable to be discharged, although it’s harder to discharged compared to
hydroxide ions.
In VERY DILUTE solutions containing
iodide/chloride/bromide ions, hydroxide ions of water will be discharged
instead of iodide/chloride/bromide, according to ease of discharge.
Sulphate and nitrate are NEVER DISCHARGED in
concentrated/dilute solutions.
A.
Concentration Solutions: - Electrolysis of Concentrated NaCl
What happens:
Ions Present: Na+, H+, OH- and Cl-
Reaction at Anode
Cl- loses electrons at anode to become Cl atoms, although OH- is
easier to discharge.
Cl atoms created form covalent bond together to make
Cl2 gas.
2Cl- (aq) --> Cl2 (g)
+ 2e-
Reaction at
Cathode
H+ gains electrons at cathode to become H atoms becoming hydrogen
gas
2H+ (aq) + 2e- -->
H2 (l)
Overall
Equation
2HCl(l) --> H2(l) + Cl2(g)
Note: any cation and anion left undischarged
in solution forms new bonds between them.
E.g. in above, leftovers Na+ and OH- combine
to form NaOH.
B. Very Dilute Solutions:- Electrolysis of Dilute H2SO4
What happens:
Ions Present: H+, OH- and SO42-
Reaction at Anode
OH- loses electrons at anode to become O2 and H2O.
4OH- (aq) --> O2 (g)
+ 2H2O (l) + 4e-
Reaction at
Cathode
H+ gains electrons at cathode to become H atoms becoming
hydrogen gas.
2H+(aq) + 2e- --> H2 (g)
Overall
Equation
Both equations must be balanced first.
The cathode equation is short 2 electrons. Hence, we
should first even them by multiplying cathode equation by 2.
(2H+(aq) + 2e- --> H2 (g))
x 2 = 4H +(aq) + 4e- --> 2H2 (g)
Now we can combine the equations, forming:
4H+ (aq) + 4OH+ (aq)
--> 2H2 (g) + O2 (g) + 2H2O (l)
4H+ and 4OH+ ions,
however, combine to form 4H2O molecules.
Hence: 4H2O (l) --> 2H2 (g)
+ O2 (g)+ 2H2O (l)
H2O molecules are formed on both
sides.
Therefore, they cancel the coefficients: 2H2O
(l) --> 2H2 (g) + O2 (g)
Since only water is electrolysed, the sulfuric acid
now only becomes concentrated.
III.
NATURE
OF THE ELECTRODE
Electrolysis
using different types of electrodes
Inert Electrodes are electrodes which do not react
with electrolyte or products during electrolysis.
Eg. platinum and graphite.
Active Electrodes are electrodes which react with
products of electrolysis, affecting the course of electrolysis.
Eg. copper.
A.
Electrolysis of CuSO4 Using Inert Electrodes (e.g. carbon)
What happens:
Ions Present: Cu2+, H+, OH- and SO42-
Reaction at Anode
OH- loses electrons at anode to become O2 and H2O.
4OH- (aq) --> O2 (g)
+ 2H2O (l) +4e-
Reaction at
Cathode
Cu2+ gains electrons at cathode to become Cu atoms becoming
liquid copper.
Hydrogen ions are not discharged because copper is
easier to discharge.
Cu2+ (aq) + 2e- -->
Cu (s)
Overall
Equation
Both equations must be balanced first.
The cathode equation is short 2 electrons. Hence, we
should first even them by multiplying cathode equation by 2.
(Cu2+ (aq) + 2e- -->
Cu (s)) x 2 = 2Cu2+ (aq) + 4e- --> 2Cu (s)
Now we can combine the equations, forming:
2Cu(OH)2 (aq) --> 2Cu (s) + O2 (g)
+ 2H2O (l)
Since copper ions in solution are used up, the blue
colour fades.
Hydrogen and sulphate ions left forms sulphuric
acid.
B.
Electrolysis of CuSO4 Using Active Electrodes (e.g. copper)
Ions Present: Cu2+, H+, OH- and SO42-
Reaction at Anode
Both SO42- and OH- gets attracted
here but not discharged. Instead, the copper anode discharged by losing
electrons to form Cu2+. So, the electrode size decreases.
Cu (s) --> Cu2+ (aq) + 2e-
Reaction at
Cathode
Cu2+ produced from anode gains electrons at cathode to become
Cu atoms becoming copper. Hence, the copper is deposited here and the electrode
grows.
Cu2+ (aq) + 2e- -->
Cu (s)
Overall
Change
There is no change in solution contents as for every lost of Cu2+ ions
at cathode is replaced by Cu2+ions released by dissolving
anode.
Only the cathode increases size by gaining copper
and anode decreases size by losing copper.
We can use this method to create pure copper on
cathode by using pure copper on cathode and impure copper on
anode. Impurities of anode falls under it.
ELECTROLYSIS OF COMMON ELECTROLYTES
ELECTROLYTE |
CATHODE |
PRODUCT DISCHARGE AT CATHODE |
ANODE |
PRODUCT DISCHARGE
AT ANODE |
EFFECTS ON ELECTROLYTE |
Acidifed water (dil.
H2SO4) |
Platinum |
Hydrogen gas (2 volume) |
Platinum |
Oxygen gas (1 volume) |
Conc. Of H+
and SO42- increase as water is removed making the
electrolyte more acidic |
Conc. Copper(ii)chloride
solution |
Copper |
Copper deposited |
Carbon |
Chlorine gas |
Removal of Cu2+ and
Cl- dil. electrolyte |
dil. CuCl2
solution |
Copper |
Copper deposited |
Carbon |
oxygen gas |
Conc. Of H+
and Cl- increase making electrolyte acidic |
Conc. CuCl2
or CuSO4 solution |
Copper |
Copper deposited |
Copper |
Copper anode dissolves |
Conc. Of electrolyte
remain unchanged |
Conc. CuSO4
solution |
Copper |
Copper deposited |
Platinum |
Oxygen gas |
Conc. Of H+
and SO42-increase, making electrolyte acidic |
Conc. HCl acidic |
carbon |
Hydrogen gas 1 volume |
Carbon |
Chlorine gas (1 volume) |
Removal of H+ and Cl- dilutes electrolyte, making it less . |
Conc. NaCl solution (brine) |
carbon |
Hydrogen gas (1 volume) |
Carbon |
Chlorine gas (1 volume) |
Conc. Na+ and
OH- increase making
electrolyte alkaline |
Molten NaCl |
carbon |
Sodium |
Carbon |
Chlorine gas |
Conc. Remains unchanged |
Conc. Sodium hydroxide
solution |
platinum |
hydrogen gas (2 volume) |
Platinum |
Oxygen gas (1 volume) |
Conc. Of Na+ and OH-
increase as water is removed, making electrolyte more alkaline |
Conc. NaCl (brine) |
mercury |
Sodium amalgam |
Carbon |
Chlorine gas |
|
PRESENTATION
Step I: The teacher explains electrolysis with its terminologies.
Step II: The teacher explains the factors that affect the preferential discharge of ions
Step III: The students chorus the factors that affect the preferential discharge of ions
Step IV: the teacher explains the electrolysis of some common electrolytes
EVALUATION
The teacher evaluates the lessons by asking the following questions:
i. Define electrolysis
ii. Differentiate between metallic conductor and electrolytic conductor
iii. State the factors that affect preferential discharge of ion
iv. Explain electrolysis of some electrolytes
This is wonderful...so elaborate. Many Tnx
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