CAPACITANCE ( DEFINITION, ARRANGEMENT AND APPLICATION)
CAPACITANCE`(DEFINITION, ARRANGEMENT AND APPLICATION)
A capacitor is a device for storing electric charges or for
storing electricity. It consists essentially of two conductors (metal plates)
carrying opposite charges. The metal plates are separated a small distance, d,
by an insulator.
The insulating material placed between the plates of a capacitor
is called dielectric substance. The capacitance increases with the area between
the plates, decreases with increasing distance, and increases with dielectric
constant.
The Capacitance (C ) of a capacitor is defined as the ratio of the
charge Q on either plates or conductors to the potential difference V between
them.
C =
Quantitatively, the capacitance of a capacitor
is a measure of its ability to store up electricity. The capacitance, C is a
constant for a given capacitor.
Factors
affecting the capacitance of a parallel-plate capacitor.
The value of capacitance depends on the size,
shape, distance separating the two plates, and the nature of the material that
separates them and the common area of plates.
Capacitors in
series and parallel.
The resultant or equivalent capacitance of any number of
capacitors connected in parallel is the sum of their individual capacitances.
The reciprocal of the equivalent capacitance of any number of capacitors
connected in series is the sum of the reciprocals of the individual
capacitances.
Capacitors in series
Capacitor in parallel
C =
Energy stored
in a charged capacitor.
This work done in charging a capacitor is the energy stored in the
capacitor. Hence
W =
W is in joules if q is in coulombs, V in volts
and C in farads.
Application
of Capacitors
Used of capacitors are: i.
Radio circuits for turning ii. Ignition
system of motor vehicles.
iii. The elimination of sparks when a circuit containing
inductance is suddenly opened e.g in induction coils.
Example
1. A
work of 30 joules is done in transferring 5 milliCoulombs of charge from a
point B to a point A in an electric field. The potential difference between B
and A is.
Solution
W= 30J, q= 5x10-3C, V =?
W =
2. A series arrangement of three capacitors of value 8ᶙf, 12 ᶙf,
and 24 ᶙf is connected in series with a 90-V battery. (i) Draw an open circuit
diagram for this arrangement. (ii) Calculate the effective capacitance in the
circuit. (iii) On close circuit, calculate the charge on each capacitor when
fully charged. (iv) Determine the p.d across the 8 ᶙf capacitor.
Solution
(i)
(ii)
(iii) charge on 8 ᶙf = charge on 12 ᶙf capacitor
(iv) Total charge, Q, = CV = 4x10-6F x 90V = 3.6 x 10-4C
p.d across the 8 ᶙf capacitor =
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